did my day course and written test for doing motorcycle MOT's today and passed!  :cool:

so just my practical to do and my plan for world domination will have begun!  :laughcont:


heres a question for ya

if you weigh 75kg.. and a bike first registered in 1990 weighs 200kg

the stopping force for the front brake is 75Kg
stopping force for the rear is 50kg

what are the percentages of brake efficiency and would they pass a MOT?


answers on a postcard to....


btw it gets even more complicated once u start adding linked brakes and sidecars!

if you weigh 75kg.. and a bike first registered in 1990 weighs 200kg

the stopping force for the front brake is 75Kg
stopping force for the rear is 50kg

**********************************************

Do you get fries with that

Congrats EB,
75% front 25% rear.
Dont you get a big book with all the answers in(once your qualified) so you can just look it up?

well done EB

when is the next part.

I wish.  :verysad:

Congrats anyway.  :bowdown:

ok answer is

front brake = 27.2 %
rear brake =  18.2 %

a most definate fail..  must have a minimum of 25% on one brake and 30% on the other.. doesnt matter which way round..


the formula you use is

           stopping force
-----------------------------------    x  100  =  %
(weight of bike + weight of rider)


now the stopping force is on which control you use (front or rear) not the actuall brake itself, because if you have linked brakes you have to add both stopping figures together for whatever control operates them so in this case if the brakes were linked  the result would be

75+50
---------   x 100 = 45.5%  
200+75

this would be a pass if both controls operated both brakes.. but if one of the controls acted independantly then it would still be a fail

complicated eh!

and i havent even started on sidecars yet!